Jaime Rudas's latest activity

See this answer: https://physics.stackexchange.com/a/43061

The Gaussian curvature ##K## of the hyperboloid ##x^2+y^2-z^2=1## is ##\frac {-1}{(1+2z^2)^2}##. Thus, when ##z=0##, the curvature...

The German Wikipedia says: Which, translated, would be: I understood that the hyperboloid didn't have constant Gaussian curvature. Am...

Yes, I think I was wrong. Although I don't know if it's possible to define curvature at the "edge" of the pseudosphere (i.e., at the...

Yes, maybe, but there is no such surface embedded in Euclidean three-dimensional space.

No, two-dimensional saddle-shaped surfaces have negative curvature but this is not constant.

Not in this case. The curvature parameter ##\Omega_{\kappa}=0.0007 ± 0.0019##, meaning its zero value is WITHIN the margin of error...

The best model of the universe we have (the ΛCDM model) is fully compatible with both a finite and infinite universe. Moreover, the most...

Do you have a reference that supports this?

Yes, maybe I didn't clarify that this was a sarcastic response.

Yes, those official scientists always try to refute everything.

Yes, but it is still worrying that more and more people responsible for this type of decisions think the same nowadays.

Do you have a reference that supports this?

Yes, but perhaps that's because the cited paper is from July 2011, while the main paper on asymmetric radiation of the Pioneers is from...

You have forgotten the relativity of simultaneity, which is less popularised than length contraction and time dilation, but probably...