Recent content by jambraun
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J
Trajectory - different start and end height, limited knowns
lol, you're absolutely right. Here's the conversion using degrees. I'll have to play with it so the projectile stays on the playfield / looks believable:- jambraun
- Post #27
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
I think that may have done it! Thanks for the help. I'll drop this into my program and see if it hits the target :)- jambraun
- Post #25
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
Sorry! I changed my values after you mentioned I could alter some variables to have the time change...that was probably a bad idea since it changes the help I'm asking for. Between you and Cwatters I'll write up my final equations and repost with the completed version. I think the answer is...- jambraun
- Post #22
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
I thought I did :/ the answer to the above came out to be -(40/106) which is still waaaay off the mark. I'm posting from my phone so I can't do anything elaborate for a bit- jambraun
- Post #19
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
I'm failing in the substitution and rearrange steps. It's always been my weakness. Can I beg you to show me what the correct equation for g is?- jambraun
- Post #17
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
ok, I need someone to check my math... here's what happens when I plug in the variables: The hardest equation by far is to find gravity (which must be incorrect). Alternatively, if I solve for gravity by hand... 40 = (175/(2*cos(70)))*2*sin(70)-.5*g*2^2 40 = 212.52-2g... Help me out where...- jambraun
- Post #15
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
Oh, I got lost when you said I could change the gravity to get the needed rise. I didn't understand if I'm solving for gravity or just choosing a greater gravity? Also, for solving the difference in Y, are you saying: But I don't have to use steps 1 and 2 from notes, just plug in the...- jambraun
- Post #13
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
Sorry, the equation variables aren't something I can guess at while running for the program to work. Plus, doesn't calculating the initial velocity from the original equation of X always land short of the mark? I believe that's why it's a 3 step process, obtaining the true time in the air from...- jambraun
- Post #11
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
6.26s is too long (unfortunately). Can I fudge gravity or angle to decrease the time? I still need to figure out how to displace the distance so the target is struck at the right height. We'll still have to talk about how to account for displacement I think. Here's what I was trying to use...- jambraun
- Post #7
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
I knew something was up...I can be flexible on time or gravity. let me post the equations I've been working with in the morning but I still think my hangup is with the height displacement. Thanks!- jambraun
- Post #5
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
Thanks CWatters, my major notes are in my notebook at home; I'll post them in the morning. I think my primary issue is displacement of X to compensate for the differing heights. I have no problem calculating the launch and land from the same altitude which is pretty straight forward.- jambraun
- Post #4
- Forum: Introductory Physics Homework Help
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J
Trajectory - different start and end height, limited knowns
Homework Statement A projectile is fired from a cannon at X-distance of 25m (X=25), height 10m (y=10), and fixed angle (53-degrees). After 3 seconds, the projectile hits its mark at different height 50m (y=50), and at a range of 175m (X=200). Gravity is normal and there is no wind resistance...- jambraun
- Thread
- Height Trajectory
- Replies: 27
- Forum: Introductory Physics Homework Help