Recent content by janisr

M is correct because it was given. Maybe It is small because it is just an exercise homework for my exam. And I think I'll go with L=160 mm, as you suggested. No diagrams was given, nor material was specified. Tomorrow I hope I will meet my teacher. Thanks for your time, it was helpful. :)

All that is given is in the picture in post #4. And with this I can not calculate shear stress τ, am I right? If so, maybe you are right and I am supposed to assume Qmax or I have to draw a beam and put on some kind of loads, but then again the Mmax will change. The book we use in our studies...

So the whole problem is in the picture. Professor just draw the cross-section of a beam and wrote down the things I had to find + he wrote M=10 kNm. I think I managed to calculate sigma_plus and sigma_minus. As for sigma_minus - it is the tension in the part of a beam cross-section that is...

Thanks for reply! :) I have question for things I have already done. If I have Moment of resistance Wmin=323.8 cm^3; Wmax=427.1 cm^3 then I get σ+= (Mmax/Wmaxx) and σ-= (Mmax/Wmin) right? Professor gave M=10 kNm. And this was the number I puted into those formulas.

I have a cross-section of a beam like this one http://imageshack.us/photo/my-images/810/img0129xf.jpg/ And I have to calculate the shear stress τ. I have these things already calculated: Xc=8cm; Yc=6.9cm Moment of Inertia Ix=2946.7 cm^4 Moment of resistance Wmin=323.8 cm^3; Wmax=427.1 cm^3...