Recent content by JasonD

I am sorry; I had just assumed you were designing a chain drive. Unfortunately, I don't have experience in the area in which you are working. A quick look through Shigley's suggests that the section titled "Force Analysis - Spur Gearing" may be useful to you.

Look through the section titled Roller Chain (17-5 in my U.S. 9th edition). You already know the input speed and you should be able to figure out the system's horsepower. At this point you can find a suitable ANSI chain number from the Tabulated Horsepower Table (Table 17-20 in my edition)...

As SteamKing implied, there is no quick and easy answer to your newest question. You'll need to read some tutorials or get your hands on some books. I learned from "Shigley's Mechanical Engineering". To give you a direction, you'll first need to know the power requirements, torque loads...

The gear ratio is equal to the inverse of the speed ratio: \frac{Tooth Count 1}{Tooth Count 2} =\frac{Speed 2}{Speed 1} This can be rewritten in any number of fashions. For example: ToothCount1*Speed1 = ToothCount2*Speed2 Or, rearrange to solve for your unknown. In your case...

Looks like I was wrong, too...

Wow, what a great question. I was completely convinced that I knew the answer until I started thinking about everyone else's reply. If you compress an object on one side with a force it will experience that force. If you add another force to the opposite side, the object will now...

In the concept I described, the actuator would need to be mounted with brackets like those used for screen door closers. A good place to look for available push/pull forces and stroke lengths is http://www.firgelliauto.com/" . I've worked with them in the past and found them to be very...

Steve, I don't completely understand your concept. What I had envisioned looks like the attached image. The linear actuator will keep pulling/pushing for as long as a current is applied. The direction of the actuator (push/pull) is changed by swapping the voltage polarity which is usually...

Hello porav05 and welcome to Physics Forums. Generally, new questions are asked by creating a new thread/topic. To ask a new question, go to the appropriate subject (for Mechanical Engineering questions use https://www.physicsforums.com/forumdisplay.php?f=101") and click on the "New Topic"...

I happen to have the seventh edition of Hibbeler's Mechanics of Materials; it sounds like the example hasn't changed. One issue I have always had with Hibbeler (I've used three of his books) is that he tends to assume you're comfortable enough with previous material to not need it repeated...

How about using a linear actuator to both open and close the door? Linear actuators have a good price to force ratio and would solve the problem of the door slamming shut.