Recent content by Jayson

  1. J

    Mathematical relationship of a thermocouple

    ok solving for t 24 = 40e^-4/t +10 14/40 = e^-4/t 7/20 = e^-4/t and then I'm lost as to how e disappears to become τ= -4/ln(7/20) = 3.81 any help in the right direction much appreciated before I go mad
  2. J

    Mathematical relationship of a thermocouple

    Hi, I've been following this up until we got to solving for 4 seconds at 24 24=10+40e^-4/τ and then became totally lost when solving for τ τ= -4/ln(7/20) = 3.81 I'm a little lost on how the 3.81 came about and not sure if its some basic maths I'm missing here, or confusion over the written...
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