Recent content by jbender

This is my work for setting x=2 in the two given equations. a(2)^3 +1 = b(2-3)^2 +10 8a+1 = b+10 b=8a-9 What equation do I substitute "b=8a-9" to solve for the value "a" ?

The point where the definitions change is at x=2. Correct?

Find the values of a and b that make the function f(x) differentiable. f(x)={ ax^3 + 1 , for x<2 { b(x-3)^2 +10, for x is greater than or equal to 2 ax^3 + 1 = b(x-3)^2 +10 3ax^2 = 2b(x-3) From here I'm unsure of where to go.