wow...
I read that and thought because it's a locomotive, then blood drained from my face.
a locomotive, a train... why the hell am I a physics major? lol
thanks! that's all I needed
Word for word:
A50,000kg locomotive is traveling at 10 m/s when its engine and breaks fail. How far will the locomotive roll before it comes to a stop?
Rolling friction for rubber on concrete is 0.02 (by the book)
a= fnet/m = (umg)/m so mass cancels out leaving a = ug = .02(-9.8) =...