Recent content by jdnhldn

So z13= 0 to 13 in the ring. First I didn't get what a ring was, then I saw an example of the clock that z12 is 12=0 and 11+1=12=0 and 12+1=13-1=0. Something in that style. Now I got it. inverse elements to 7 in ring z13 = 2 Thanks guy.

The "(n)" made me see it clearly. Thank you so much.

I am sorry that I got you confused by the translation. Yes, as Mark44 mentioned, it means remainder. This is exactly what I am looking for and it looks familiar :) But I don't get how 7^35=2^35 (mod 5) Please explain?

This was a note from the class, I've forgotten what k means in this one. May I please ask you what you think it means?

Homework Statement Find the least positive rest in division of 7^35 with 5 Homework Equations (7^35)/5 The Attempt at a Solution 7^35=378818692265664781682717625943 => 378818692265664781682717625943/5... Uhhhhh this is not the way I am supposed to take right? :cry:

Homework Statement I need to find the inverse to element in 7 in ring Z_{13} Homework Equations 7^-1 in Z_{13} The Attempt at a Solution Needs to find X so that, 7x=1 in Z_{13} => 7x=1+k*13 And then my notes was messed up :(

Thank you, I've got it. Now I saw the lights.

Thank you, but is there a quick way to see if the equation is solvable or not? Or do I need to go all the way to find out?

Homework Statement I am trying to determine if an diophantine equation is solveable or not. And got stuck at one point. Homework Equations 61x+37y=2 The Attempt at a Solution I've found the gcd(61,37)=1 by: 61/37=1 %24 37/24=1 %13 24/13=1 %11 13/11=1 %2 11/2=5 %1 2/1=2 %0 So gcd(61,37)=1...