ah success! haha that's like the first answer i got completely right XD
ok one more quick question on a different problem, I am pretty sure i know how to do this one only I am a tad bit confused, i don't find it difficult enough to post a new thread so ima post it here an see if it'll get...
In the sample it says
The average kinetic energy of the entire gas is
K = N(3/2 * kT)
I tried it both E / that and E over the thing you posted and both answers were wrong? do i have the value of k right = 1.38e-23?
ohhh ok cool, nevermind i thought there was something to do with the mass of a single molecule...
anyway and then for part be it says the ratio of such and such:
would that be E / Kavg of the gas = E / N([3/2]kT) ?
so E / Kavg = 1.55e-20 / (3.3418e * [3/2] * 1.38e-23 * 302.7) = 7.402e-23?
an incredibly small fraction, then? hmm so
well the problem is asking for E based on n = the number of molecules per gram of sample, so since 3.34e22 is the number of molecules per gram of sample, would then E = 1.55e-20?
or am i somehow supposed to implement the use of a single molecule...
I'm honestly not quite sure
it says En = the heat of vaporization (518cal/g) where n is the molecules per gram. so that means En = 518cal/g, n = 3.3418e22 (whats the unit for this, mols?), then would E = 518cal/g / 3.3418e22 ?
that doesn't sound right seem's like an incredibly small number...
i guess i was trying to find the moles? or something, is it not
n = Msample / M
where M = molecular mass = 18.02g for H2O?
i guess i only got halfway, that would be the number of moles, correct?
then to get the number of molecules you multiply that by Avo's Number
(1/18.02mol) *...
I'm really starting to hate this class, the lecture didn't even begin to explain any of this I have no idea where to begin. We've been working on change in internal energy and work done on/by a gas, etc, and we get a question like this on the homework:
Water standing in the open at 29.7°C...
I don't understand that part, how do you determine if it isn't enough?
using this example, Q for the ice to 0 degrees is 1847040J (for both ice cubes), and Q for the water is 19213740J from 27 to 0 degrees
How do you determine if that is enough heat or not enough heat? Or is my math wrong?
so from what you said here's what I am getting:
C ice * M ice * (0 - [-13]) + L * M ice + C ice * M ice * (Tfinal - 0)
[heat to ice] + (heat of fusion) + [heat to melted ice] ?
and you do that with both cubes of ice?
edit: i just tried that and got the same answer (T0 =...
First of all, hi, and thanks ahead of time... I've been working on this homework for almost a week, even asked the teacher for help but still haven't been able to figure out what I've been doing wrong/missing. its online work so ill copy paste it
Homework Statement
(a) Two 32 g ice cubes...