Recent content by JI567

What do you mean by F*F though? I just need to find |F(iw)|^2...

Hey man, do you know anything about plotting bode magnitudes or step response plots?

hmmm so that makes my denominator have A^2-B^2, but it should really be A+Bbs...also how do you get the 1 in the numerator? I mean in the denominator i multiply with denominators complex conjuguate? what about numerator? is it going to be multiplied by numerator complex conjugate or denominator...

That's because the complex term "i" is with it? don't you see I changed the sign infront of the "i" term in the numerator? As far as I know for any positive complex number x+iy, its conjugate is x-yi, so just changing the sign. Don't know what type of complex number did you study

I get how I am supposed to use the trick 1...but its the trick 2 I can't really figure out how to use wisely...I tried to use trick 2 to replace Wn^2-w^2 but doesn't fit there...what do you use trick 2 for?

If you look properly you will see I have already done that...the 3rd step incase you still can't see it...

F(iw) = ## \frac {(iw)^2+2ζaWn*wi+Wn^2} {(iw)^2+2ζbWn*wi+Wn^2} \ ## = ## \frac {-w^2+2ζaWn*wi+Wn^2} {-w^2+2ζbWn*wi+Wn^2} \ ## = ## \frac {Wn^2-w^2+2ζaWn*wi} {Wn^2-w^2+2ζbWn*wi} \ ## x ## \frac {Wn^2-w^2-2ζbWn*wi} {Wn^2-w^2-2ζbWn*wi} \ ## = ## \frac...

Homework Statement Question is when F(s) = ## \frac {(s)^2+2*ζa*Wn*s+(Wn)^2)} {(s)^2+2*ζb*Wn*s+(Wn)^2)} \ ## prove that ## \ {|F(iw)|}^2 \ ## = 1 - ## \frac {4(ζb^2-ζa^2) \tilde w} {(1-\tilde w)^2+4ζb^2 \tilde w} \ ## when ## \tilde w \ ## = ## (\frac {w} {Wn} )^2 \ ## Homework Equations...

That's alright...can you check the latest t =0.25 I posted in post 17...is that correct sketch for y?

In that case my first middle sketch for t=1 is correct then if you have a look. I do have -0.5 for 0 to 1 and 0 for -1 to 0. Why did you say it was wrong initially then?

And for t=1 are the middle and bottom part correct now?

Is this correct for t =0.25 y sketch

What am I doing wrong for the middle and the bottom sketches? I mean for the middle part specially I am considering the range D(x) = -1 if -1<x<0 so as t = 1 i am adding -1+1<x<0+1 so my range becomes 0<x<1 for Φb = -0.5 and when considering D(x) = 1 if 0<x<1 for t = 1 I am adding again so...

For t=0.25 is this sketch for y correct then and for t = 1 by middle sketch you mean the Φb is not correct and other two are correct? and as for considering x>0 for combined solution, that's what I have done for the y sketch of t = 1...I have ignored the x<0 region of the Φb sketch...but...

I mean when t=0 how is the boundary condition being satisfied? Also can you confirm if sketch for t=1 is correct