I see what you are saying. I have had problems such as that and I did have to use a different approach for that problem. Thanks for your help and thanks for looking at my problem. I think I was making it way harder than what I needed to and was really second guessing myself :)
I think i screwed up my conversions though. does my answer seem high. I times by 12 and I am thinking I should have divided by 12.
Out of curiosity what's another way I could have solved for the moment?
thats what my formula tells me to do. I have a cantilevered beam with a fixed connection @ point A, and it caries a uniformly distributed load of 15 kips/ ft for 11 ft.
my formula that I found for this situation says my Mmax = wL2/2
so this is what I came up with as I am running out of time.
w = 15 kip/ft X 1000 lb/kip = 15,000 lb/ft
Mmax = wL²/ 2 = 15,000 lb/ft (11ft x 11ft) / 2 = 907,500 lb-ft X 12 in/ft = 10,890,000 lb-in
Thus my Mmax =10,890,000 lb-in
For my forces I assume the sum of all forces must equal 0...
This is what seems odd. What I think I have to do seems way to simple which is why I think I am heading in the wrong direction.
For my force I am thinking the sum of my forces need to equal 0, thus my force at point A will be negative 165 kips. right?
For my moment I think I have to take...
I am really stuck on this and am looking for any type of direction anyone can give. I have an 11 foot long rigid body that supports a 15 kip/ft uniformly distributed load. I need to find the reacting moment in (lb-in) and force in (lb) at point A.
Point a is at the pined connection (see...
Hey everyone I am wondering if someone can just double check my work and formulas to see if I did this correctly. Thanks!
A 1.0-m rigid horizontal support is hung by two cables as shown. One cable is brass and the other is high density polyethylene plastic. At room temperature (21° C) the...
ok I am still having some trouble. nothing is checking out correctly.
if I use D⁴ = πJ / 32 I get .0072788276 then I take that to the power of .25 and get .2920891052
My issue is this. if I assume that is D and plug it into J=πD⁴ / 32 I should get my original J value of .0741415291 but I...
i see what your saying about the bending now and I do agree with you. I think this book just brushed it off though, I think at least lol.
so I am assuming I got J correct then hey.
so if J=πD⁴ / 32
my formula should be D⁴= πJ/32 right? I am not sure ow to do D⁴
No I don't know the principal stress equation?
I guess I am confused by what you mean 'first part' are you referring to part a? did I get that incorrect? When I back check it it comes out perfect.
whats confusing me is the addition to the concept of bending into the mix when the problem...
Ok that confuses me even more. The question only asks for the diameter size so torsional stress does not exceed 1 degree. My book does not say to calculate bending in any of the examples and says to find the angle I need to use TL / JG and the result is in radians then I have to multiply that...
attached is a diagram.
It looks like I miss typed my problem for 'B' it should read this.
Determine the minimum diameter rod so that torsional strain does not exceed 1.00 degrees.
Sorry about that. for some reason a and b were the same. I solved a already but am stuck on B
hey everyone I am stuck on a problem and would appreciate any guidance you could give me.
here is the question:
Much as in exercise 8.1, the end of a .75-in-diameter rod is fixed to an immovable plate. the length of the rod is 18.0-in. A 50-lb weight is attached to a 16.0-in lever at the...