Recent content by Jimmy23

Hi, I know this is quite a basic question for you guys but it's helping me understand. -(-b)-3b+c=1 or -a-(3a)+c=1. Are these both acceptable ways of doing the working out? Also when you say 'I think you mean a negative times a negative is a positive' Am I right in thinking the...

Thanks you for your help guys, I appreciate it. I think the part that tripped me up was when you substitute one for the other I overlooked the fact the negative is still there and so a negative plus a negative is a positive.I was asking A=0.5 or 0=0.5-A or -0.5=-A more so for reassurance that I...

Thanks for your help. Sometimes it's easier to talk it through with someone who knows what they're doing. Its ard to teach yourself something you don't know. So A=0.5 or 0=0.5-A or -0.5=-A B=-0.5 or 0=-0.5-b or 0.5=-b C=0 or -C=0 What level of education do you think I'm at...

If you were to substitute b with -a. Would 2a+c=1 be true?

Yeah sorry that's what I meant

Ahh I think I see what I've done. [L] -a-3b+c = 1 Substitute a for -b. Therefore, -(-b)-3b+c=1. -(-b) is just b. So you get b-3b which is -2b. -2b+c=1. Is this correct? This is all new to me. I'm a student. Thanks

Hi, You say my first question correct (a=-b and b=-a are both correct) if you then plug these into [L] -a-3b+c = 1 separately. You end up with both 1=c-b-3b and 1=c-a-3a respectively. But then you answered question 2 as 'No, neither is true' what am I doing wrong? if you were to substitute...

Hi, thanks for your reply. I'm a little confused on the following. 1) am I right in saying a=-b and b=-a? 2) when you plug are both of these true 1=c-b-3b and 1=c-a-3a? 3) if I were to pick one of the above. Let's say, 1=c-a-3a. Why is it 1=c-2a and not 1=c-4a? 4) on the next step (add...

Hi, Ive been trying to get past this last step i can't work out how people get A=0.5 B=-0.5 C=0 from [L] -a-3b+c = 1 [T] -2a-2c = -1 [M] a+b=0 I can't find help anywhere. Can someone please explain how it's done