Recent content by jmarsiglio

My response was meant to help you find the answer... I could show you but I'm not sure if that's allowed.

aha... I guess I have to multiply everything by two then -.- Thanks. (actually divide)

I don't think the catalyst counts though, it just speeds up the process. So 10ml, I'll do this. Correct?

AMAZING! One more thing! The volume of the solution is the catalyst and the hydrogen peroxide? 20 ml in each case? Or just the h202: 10 ml?

what does 0.2% mean? How many grams per how many ml? and 5%, how many grams per same amount of ml? Think about how you can dilute the 5% in order to make it same ratio as 0.2%. If the ratio of 0.2% is for example 1:5 and the other is 1:2 (they aren't), then you would 3 more ml for each gram...

Yes, several times. It says "For each experiment, determine the initial rate of reaction. That is convert the volume, or mass, or increase in pressure of O2 within the time interval to get an initial rate of mol O2/(L*S). Using the stoichiometry of the reaction, convert this initial rate to a...

Okay, nevermind, the question specifically says to convert th volume of O2 within the time interval to get the reaction rate, so it can't be that, if so what would be the point of getting the values for the volume. edit: wouldn't it be the same... what the heck is the point of getting these...

Homework Statement http://scc.scdsb.edu.on.ca/Students/onlinecourses/Sikora/sch4u/v12/64.pdf That is the lab I have been working on. I've done the lab but I am answering the questions. I don't understand the Analysis question #1. How do I calculate the reaction rate for oxygen if I don't have...