Recent content by JMWM

ooops, sorry. got you. thanks!

yeah that's what I noticed. but well ok for km/h I get 1.65 and then for hours 4. so this is my equation: 1.65 km/h /4h and then I get .4125... eek. I know I'm doing something wrong.

awesome. another question, for instance 1.5 h, ok do I convert that into minutes? and if so do I take the .5 as half or as 50, as in fifty minutes. 1 hour and fifty minutes or 1 and a half or 90 minutes or 110 minutes? wow, I ask a lot of questions.

yes. thank you so much. wow there's a lot of stuff I need to learn. but I'll get there. thank you so very much, I truly appreciate it. =)

well its a review sheet, the teacher gave it to me. distance/t or do I use: av. velocity= total distance/time

I move the decimal twice. I believe. Wow, I seriously need to memorize all the convertions.

oh ok. cool. but oh gosh, let me try it. but well I'm not really sure what to do.

oh I don't know, I mean I just did it in the calculator. well s and then m/s^2 isn't that m? blah, I'm lost. and in my answer its supposed to be 19.6 cm.

Homework Statement A hiker travels south a long a straight path for 1.5 h with an average velocity of .75 km/h. then travels south for 2.5 h with an average velocity of .90 km/h. What is the hiker's displacement for the total trip? Homework Equations The Attempt at a Solution For...

oh well its supposed to be cm, do I have to convert or what?

ok so its: (0)(.20)+((9.8)(.20)^2)/2 =.196 hm...what am I doing wrong?

ok many thanks!

ok, kind of there, but u- is initial velocity isn't that 0, at rest, when mulitplied to the time it goes to zero, doesn't it?

or wait...I think I go it. 9.8 * 2?

hm..I'm not sure, I'm still confussed...