Recent content by joaofbi1

No use now, I'll be going to bed and it's due in tomorrow. I'll just ask the teacher how to do it. But I think I may have got it on my own anyway by using Vr=(R1/(R1+R2)x6

I still don't understand but thank you to everyone that helped me.

So once we know that the current going through the 10k Ohms resistor is 0.55mA how do we then do it? Shall I convert the 0.55mA into volts then do the same operation as above?

Could I not just simply do 6V/10kΩ to get 0.6 instead of doing

But where exactly did you get 0.55mA from? That has completely stumped me.

So how do I Calculate how much mA I have lost through the resistor?

So how do I calculate how much mA I've lost through the resistor? What formula?

Ok so I'm home, so this is what was calculated 3.3A x 10KOhms = 33Volts through the 10kOhms resistor. Then what do I do after that operation?

Im not at home yet so I cannot answer that. But after I see how much current the 10ohms resistor takes then do I use the current amount of current I have after the 10kohmd resistor and use the same calculation on the 3.3 resistor?

Im quite confused, what calculations would I need to perform?

So once I get the current for the 10.8 resistor do I divide that current by 1and 3.3

So once I've calculated the current through the 2.2 and 10 resistor then what calculation would I use?

I got the total current across the whole circuit of 3.3. So the voltage across the 2.2 resistor would be 3.3 X 2.2? But how would that help me find the 3.3 value?

Oh I understand what you mean now, so once I've found the total current what formula do I use to find the current going through the resistor?

What do you mean by draw circuit paths?