Recent content by joeth04

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Alright I had a midterm in my physics class today, and was completley stumped on this problem. Either I'm missing an equation or just not getting it, if you could lead me in the right direction i'd appreciate it. I also am attaching a picture of the problem that I drew in paint. Homework...

V(elevator) = 0+a(4.0)? i don't understand how to do it, that's why i posted on here lol could you show the solution for this one so i understand how it works? :/

i don't even understand what this statement is trying to say: "between the time when a ball leaves one of his hands and the next ball in one of his hands"

Homework Statement John is practicing juggling three balls at once. He determines that he can perform this act, so long as there is a 4 s interval between the time when a ball leaves one of his hands and the next ball in one of his hands. (seems like the wording is messed up) a)How long must...

Homework Statement An elevator accelerates from the ground with a uniform acceleration 'a.' After 4.0 seconda, an object is dropped out an opening in the floor of the elevator and that object hits the ground 4.5 seconds later. a) what is the value of the acceleration 'a?' b) How high was...

Alright guys, the final product is finally complete! Here are the equations after measuring the displacement of the MAT and not the spring haha. U(t) = (1/2)(k)(x^2) U(t) = (.5)(4681.364 N/m)(.3048 m)2 U(t) = 217.455 Joules U(g) = (m)(g)(h) U(g) = (70.4 kg)(9.80 m/s^2)(.4699 m)...

Wait a second lol.. When I am measuring the displacement in U(s) am I supposed to be measuring the displacement of the spring or the displacement of the mat?

1/2 inch standing, 7/8 of an inch first jump, and 5/4 of an inch when landing 2nd jump does the number of springs have anything to do with that, or the fact that it is a large trampoline.. not a small exercise one or whatever. also, i suppose we could make up numbers to make our project...

U(jump1) = (1/2)(k)(x^2) U(jump1) = (.5)(4681.364 N/m)(.022225 m)^2 U(jump1) = 1.1562 Joules U(g) = (m)(g)(h) U(g) = (70.4 kg)(9.80 m/s^2)(.4699 m) U(g) = 324.193 Joules U(jump1+g) = 325.3492 Joules 325.3492 Joules = (70.4 kg)(9.80 m/s^2)(h) height of 2nd jump = .47158 m = 18.5661...

good thinking lzkelley, you've been huge help on this project! i'll let you know how it goes tomorrow :smile:

All right, so earlier tonight my friend and I did a little testing. He weighs 70.4 kg and has a vertical of 0.4699 m (18 1/2 inches). And the spring is displaced a half inch (0.0127 m) when he was standing in the center of the trampoline. So here are the calculations... U(s) =...

Thank you guys for all the ideas, hopefully I'll get some testing done this weekend and let you guys know how it goes and if I need further help. :smile:

Alright dude, I'm in my high school Honors Physics course.. Sorry for being for the most part helpless, but how would I go about doing that?

In order to find the spring constant if needed eventually, I removed a spring and suspended 60 pounds then measured how much the weight caused it to stretch. After converting the units to metric here's what I came up with. k = (27.2155 kg)(9.81 m/sec^2) / (0.05715 m) k = 4671.63 N/m...