Recent content by johnibr5

  1. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    Yeah, I tried that but messed up near the end. But I figured it out now, thanks
  2. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    Thank you so much! I finally got it, I knew I'd miss a little step throughout the way. Thanks again and now I can write this exam and enjoy comp sci!
  3. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    My calculus course book shows how to solve it differently so I'm not too sure about the 2 step method :p
  4. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    Wow I feel dumb for forgetting the cos2A..
  5. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    thanks for the help, but I messed up somewheres I'm pretty sure. Could you tell me where I messed up? Thanks a bunch
  6. J

    CosA=cos2A+cos4A where 0°<or equal to A<or equal to 360°

    Hey guys, I'm doing a correspondence course in calculus and I have literally one last question to complete and I am having the worst luck solving it. I am coming here to ask because I hear the best minds are on this website. Anyways the question, is: Find the solution to the nearest angle...
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