well, how about final velocity? is it also zero? it seems not but i thought it should be zero after the 20 sec...omg
ok here is what i have changed,
for t = 16
v = a(16)
d= 0.5*a*(16)^2
for t = 4
v = 16a(4)
5100-d = 16a(4) - 9.8 (0.5)(4^2)
5100 = 128a + 64a - 78.4
solve for a? i...
Homework Statement
A 1000kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16s, then the motor stops. The rocket altitude 20s after launch is 5100m. You can ignore any effects of air resistance.
What was the rocket's acceleration during the...