Oh wait I think I just got it... 28.13 degrees C.
From saying that when they are in thermal equalibrium
(0.092*500)*(300-t(final))=(1*4000)*(t(final)-25)
13800-46t=4000t-100000
and working from there until 113800/4046=t
=28.13C
btw my bad for putting this in advanced...
I know its not meant to be a hard question but I just can't get my head around it. A 500g copper pipe is heated to 300 degrees C, if it was dropped into 4KG of water (approx gallon) at 25 degreesC what will be the final temp?
Change in internal energy (U)=heat or energy transferred to object...
YES! I got it there I think.
If the max acceleration for the crate is 2.943 then I plugged it into the equation
v^2=u^2+2as
0=380.25+2(2.943s) therefore 380/2=2as, as=190, 190/a=s.190/2.943=64.6m
Just a we bit off but that's probably because of my accuracy rounding up etc...
thanks very much...
by the way people when I said the answer was 64.3m it doesn't tell you this in the question. My lecturer just put it at teh end so you would know if you did it right or not
thanks
ahh right right i see. And is this the same when working out your point 1?
em force of friction is the coefficient of static friction*force acting on the crate?
which is 0.3*(m*9.81)= 2.943m?
Yea but how do I work out the mass? F =ma but I only have acceleration so I can't work out the force you see? at least I think. Does it all work out for you guys when you do it? Maybe I've been looking at this too long and my brains wrecked :/
hey thankyou tiny-tim! I can't believe i have never found this place before. I just realized I had messed up the value for the coefficient. edited it there. thanks for the help guys I am going to work through it now.
Just one question though to Meithan, how can I work out the force...
hey people i read a post similar to my problem but just couldn't get it... this is my problemThe coefficient of static friction between the
flat bed of the lorry and the crate it carries is
0.30 Determine the minimum stopping
distance s that the lorry can have from a
speed of 70 km/h with...