Thank you. I am getting a better picture now. I have also found Amndrew Hamiltons website very interesting (http://casa.colorado.edu/~ajsh/)
With reference to your reply as to the apparent size of a BH from a distance, I have learned that inside 1.5 Schwartzchild radii, no orbits exist, stable...
Thanks for these great links.
Your formula, Peter, reduces to Rs/c which seems to suggest that, from the point of view of the falling observer, the radius of the BH really is something like Rs the Schwartzchild radius. Now I had understood that while the circumference of the BH was equal to...
A number of recent threads have discussed what happens when an observer falling into a massive black hole passes the event horizon. What I would like to know is this. For a massive BH of mass M, Schwartzchild Radius Rs, how long would it take for such an observer (who, presumably crosses the...
That's really interesting and confirms Biggins analysis.
The reason why the phenomenon seems to be so counter-intuitive is that the table has to provide an upwards force on the chain (over and above the normal reaction force on the chain) and, bizarrely, the chain seems to be using this...
OK I give in!
The tension in a chain flowing along its length in an arbitrary curve is constant and equal to λv2.
It wasn't Voko's mathematics that persuaded me but John's refutation of my thought experiment. When you start pulling the chain along its length, each bead in the loop has to...
Yes - how silly of me! I knew when I wrote the post that I shouldn't have mentioned energy as that was not my point at all. All I wished to demonstrate was that you can devise situations in which the tensions at the two ends of a freely flowing loop of chain can differ. (In fact, if you consider...
I have been giving your arguments serious consideration but I remain convinced that the impressive mathematics you quote is not applicable to the dynamic situation which we are trying to explain and that the tensions at the top of the two straight sections of the fountain do not have to be...
I think you have an interesting point here. If you look at Mould's video closely you will see that the rising part of the chain is fairly straight; then the chain makes a sharp right angle bend followed by a more gradual arc into the falling section. Now all of us (myself included) have been...
I thank you for clarifying the difference between our two theories and it would appear that the main difference between them is in the different predictions for the speed of the chain. I believe that Baggins and Warner would predict a speed of √ (h1 + h2)g whereas I predict a speed of √ (h1 +...
I had in mind the theory that motion through the aether would cause a real physical contraction in the length of one of the arms of the MM interferometer and that the absence of a measurable shift in the fringes implied that the Earth was 'dragging the aether along with it'
I am sorry if my use...
While I still don't quite follow your logic, Voko, I can see that for a chain moving in an arc of a circle of any radius, the tension which is as a result of the necessary centripetal forces is equal to λv2 and - crucially - it is not dependent on the radius.
If you imagine a cowboy lassoo...
Voko - the proof you submit leads to the, perfectly correct equation
[T−λv2]∂r/∂s=c
Now ∂r/∂s is the rate at which the vector r changes with distance along the arc s. Since the proof you quote is usually to be found in textbooks in the chapter on motion in a circle, it is almost always...
gwellsjr - Thank you for the reference to one-way speed of light. If I have understood correctly, the statement that the one-way speed of light is the same as the two-way speed (as implied by Einstein's second postulate) is equivalent to the statement that the one-way speed of light is isotropic...
Yes, I see your argument but I am not sure how best to counter it. If 'the arc' was a rigid body you could indeed deduce that it would undergo an angular acceleration - but the arc is not a rigid body; it is composed of individual beads acted on by internal forces and these are the only forces...