thank you grogs, things are clearer to me now :smile:
Do i understand it correctly : When i would use nuclear masses for my computation, a difference of 511 MeV would be sufficient for positron emission?
good bye...
In positron emission, a proton is converted into a neutron, a positron, and a neutrino:
p --> n + e + v
this conversion occures only in a nucleus, because this process consumes energy (the neutron and positron have a higher mass than the proton).
The energy needed is twice...