Recent content by JonathanH13
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J
Proton travelling through a magnetic field
Ah, I think I see the error with my calculation. I am now using X = Cos(alpha)*(Velocity*1e-9) That is, if velocity is distance per second, and I require distance per nanosecond, hence(Velocity*1e-9). This delivers x and y values that describe a circle with the correct radius! Thanks!- JonathanH13
- Post #5
- Forum: Introductory Physics Homework Help
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J
Proton travelling through a magnetic field
Thanks for your reply. You describe angular position, but I require cartesian coordinates in order to simulate this: I calculate alpha = 2pi*(t/T), using t = 1e-9 (1 nanosecond), and T (Period of one revolution) = 131.19e-9 seconds This gives me an alpha of 0.0478 (is that in Radians?)...- JonathanH13
- Post #3
- Forum: Introductory Physics Homework Help
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J
Proton travelling through a magnetic field
Homework Statement I am having trouble with a basic deflection problem - a single proton traveling through a magnetic field: v = Velocity of the proton = 6 000 000 meters per second (1/50th the speed of light, so no relativistic effects) B = magnetic field strength = 0.5 Tesla...- JonathanH13
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- Field Magnetic Magnetic field Proton
- Replies: 4
- Forum: Introductory Physics Homework Help