I really don't consider myself good at calculus at all, but isn't that what i did?
to find derivative of cos(30 - x) when x and '30' are both in degrees..
= cos(∏/6 - ∏/180(x)) now to find derivative..
=-sin(∏/6 - ∏/180(x)) * (-∏/180)
=∏/180*sin(∏/6 - ∏/180(x))
?
What do you mean 'formally'?
If they are not in radians when I get to the chain rule, this will happen
derivative of cos(30 - theta) = -sin(30 - theta) * (-1) = sin(30 - theta)
but if I convert to rads..
derivative of cos(∏/6 - ∏/180(theta)) = -sin(∏/6 - ∏/180(theta)) * (-∏/180) = ∏/180...
Hi all,
The following is part of a part, of an assignment for my MATLAB course for uni.
For most of the ODE solvers in MATLAB you also have to be able to solve the question numerically - and this is the component of the question I'm doing here..
The equilibrium equation of an arch...