Homework Statement
A boat, propelled so as to travel with a speed of 0.50m/s in still water, moves directly across a river that is 60m wide. The river flows with a speed of 0.30m/s. (a) At what angle, relative to the straight across direction, must the boat be pointed? (b) How long does it...
Okay, I've got most of my research done. I just need to know how does the weak and strong salt solutions alter the structure? I've seen it listed in places that it works the same way as acids and bases, but it never really goes on to explain how. I really need to know how to understand this...
Hey, I have some homework questions and I'd appreciate some clarification.
As a class we did an experiment where we put egg white into seven different test tubes, and then introduced seven different solutions, one to each test tube. The different solutions were weak & strong salt solutions...
Okay, I have uploaded the question to imageshack because it would be to difficult to understand the question without the diagram. Basically, I've done a lot of work on it and know I'm on the right track. If someone could point out where I have made a mechanical error it would be greatly...
A ball is thrown upward at an angle 30 degrees above the horizontal and lands on the top edge of a building 20 m away. The top edge is 5m above the throwing point. How fast was the ball thrown?
ANS 20 m/s.
I just can't seem to get this. It looks like there is a piece of info missing but I...
Yes I know that number looks retardedly big. I copied it from the board but I'm sure she just made a mistake writing it. Just thought I'd post it incase you guys needed it.
Alright, here is another problem I'm having trouble with. I used a technique I got off of someone on my other thread, and am just looking to see what should be done next.
Alright so first I got my equation for the surface area of a cylinder:
SA = 2(pi)rh + 2(pi)r^2
and converted 500mL to...
Sorry about that mate. Least I could have done is checked over my calculations before asking. I just did it again your way and got the answer. Thanks for the help bro it's appreciated. :biggrin:
Okay so if my volume equation is
v = pi(r^2)(h) and I want to get rid of the radius, I simple take the information I was given...that the heigh is one fifth the diameter of the circle and for the equation h = 2r/5. I then rearrange it to say r = 5h/2 and substitute that in?
Then it makes...
I've been working on this problem for a while now and I can't seem to make it work. Maybe I could get a hint?
I understand I'm given dv/dt = 180 as well as r = 6 and h = 2r/5 = 36/5
The equation I'm using is v = Bh/3 or v = (pi)(r^2)(h)/3
I go on to take the derivative and input my...
I would guess it is because with your arms over your head, they are further from your bodies center of mass, meaning it would take more energy to sit up.
Okay thanks man! I used what you said and eventually figured it out. Interesting how it looks so hard but once you know how to do it - it seems almost like common sense :shy: .
I have one more though. I have done most of the work, but the answer I'm getting isn't the right one. Let's see what...
I have a pretty tricky question here and I can't seem to figure it out. I just maybe need a slight hint?
Both rafters are 3m long and the tie rope is tied around them 0.5m from the bottoms.
I've been playing with this for quite a while now so any little hints would be appreciated. Maybe...
Ahhh okay I did it now!
Because this FBD will be tilted, the gravity will be -mgcostheta which makes it -0.940mg.
So the equation would be
0.348mg = T - 0.940mg
1.29mg = T
Thanks so much for your help man! Appreciate it!