Recent content by Josep767

Ye I know, the bullet weight is 0.2kg i checked it twice because it seemed to heavy for me. If you translate the exercise with google translator you can see that the bullet goes through the block.

Now I need to calculate the angle that the block would do, but I'm pretty much stuck.

Okey so what I've done is: I assumed a parrabolic shot from initial X=0 and final X=5, initial Y=1 and final Y=0 I calculated the time, 0.45secs and calculated de horitzontal speed: 11.06m/s Then I applied the momentum formula mb(mass of bullet) and mm(mass of the block) mb·vb+mm·vm(which is 0)...

In this kind of exercise I have to show all the steps and explain them, the only problem is that I'm doing it in my language so I'll have to translate it.

Okey, now I am solving the exercise assuming that, once i finish it I'll post it here and we can comment the results and if you agree or not, ty

Well, I suposed that when the bullet leaves the block it makes a parabolic movement from Xo(initial position)=0m and Xf(final position)=5m and Yo(initial height)=1m and Yf(final height)=0m, but the statement doesn't confirm that so I'm not 100% sure

Yes! It is catalan :)!

Well, I've been thinking about the problem for more than 2h, this is my last resort

Does anyone know how to solve this problem? I translate the full statement: A 200g bullet is shot against a ballistic block passing it through and making an inelastic collision. The initial speed of the bullet is 200meters/second, the mass of the block is 3kg and the string that holds the block...