Recent content by josephsuk

I am not exactly what follows in the next steps. Would integrating y' d(y') give me ((y')^2)/2 or something else? If it does give me that answer, then I get y to be y=\frac{5}{2}x\sqrt[5]{\frac{-16}{3}}

It appears to be logical to use separation of variables to get y'd(y')=8y^-4dy and then integrate to get the solution?

1. y''y^4 = 8 I tried almost every method I know, including laplace transforms, variation of parameters, reductin of order, v=y' substitution