Recent content by joypav
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J
MHB Probability of Having a Totally Dominating Set (Probabilistic Methods)
Another proof for your consideration (I was busy busy busy working on problems today!). Proof: Fix $v \in V(G)$. G is r-regular, so we know $|N(v)|=r$. Label $v$'s neighbors $u_1, ..., u_r$. Let $A_{u_i}$ be the event that $u_i \in S$ and let $X_{u_i}$ be its indicator. Let $X_v = \sum_{i=1}^r...- joypav
- Post #2
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Minimum Degree of a Random Graph (Probabilistic Method)
For completeness, I will post a "proof" I came up with. As you can see, at the end I skipped over some much needed justification that I couldn't seem to figure out. Some help with this would be appreciated! However, I do think that my general idea is correct. Proof: (a) Let $G \sim G(n,p)$...- joypav
- Post #2
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Minimum Degree of a Random Graph (Probabilistic Method)
Problem: Suppose that the function $p : N \rightarrow [0, 1]$ satisfies $p >> n^{-1}ln(n)$ (i.e. $n^{-1}ln(n) = o(p)$). (a) Prove that as $n \rightarrow \infty$, the random graph $G(n, p)$ has minimum degree at least $\frac{np}{2}$ almost surely. Idea: Look at the degree of each individual...- joypav
- Thread
- Degree Graph Method Minimum Random
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Probability of Having a Totally Dominating Set (Probabilistic Methods)
Problem: A vertex set $S$ in a graph $G$ is said to be totally t-dominating, for a positive integer t, if $|N(v) \cap S| \geq t$ for all $v \in V (G)$. Suppose that r, t, n are positive integers such that $r > 2t$ and $t \geq \frac{14}{3}\cdot ln(2n)$, and let $G$ be an r-regular n-vertex graph...- joypav
- Thread
- Probability Set
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Possible combinations for six digit license plates, numbers 0-9 and letters a-z.
Is the only difference that three have to be numbers and three have to be letters? Because your calculation "10*9*8*26*25*24" suggests that repetition is not allowed. However, if repetition is allowed and there must be three letters and three numbers, we can find all unique combinations as...- joypav
- Post #2
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Proving Turan's Theorem (Dual Version) and its Implications for $ex(n, K_{p+1})$
For completeness, here is the proof I wrote. I'm not sure it is correct! May be some mistakes in the details. Known Theorem: Define $T'(n,q)$ to be q disjoint cliques with sizes of vertex sets as equal as possible. Let G be a graph with n vertices and $|E(T'(n,q))|$ edges. Then, $$\alpha (G)...- joypav
- Post #2
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Proving Turan's Theorem (Dual Version) and its Implications for $ex(n, K_{p+1})$
I have already proved that for a graph $G$ with $n$ vertices and $|E(T'(n,q))|$ edges, $\alpha (G) \geq q$. Additionally, if $\alpha (G) = q$ then it must be that $G \cong T'(n,q)$. Apparently this is the "dual version" of Turan's Theorem. How does this theorem imply Turan's? That $ex(n...- joypav
- Thread
- Dual Theorem
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Are Events in Random Graphs from G(n, 1/2) Independent?
Let $n$ be a positive integer, and let $G$ be a random graph from $G(n, 1/2)$. Let $e_1, . . . , e_{n \choose 2}$ be the possible edges on the vertex set ${1, . . . , n}$, and for each $i$, let $A_i$ be the event that $e_i ∈ E(G)$. Prove that the events $A_1, . . . , A_{n \choose 2}$ are...- joypav
- Thread
- Graph Random
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Weak Convergence to Normal Distribution
Problem: Let $X_n$ be independent random variables such that $X_1 = 1$, and for $n \geq 2$, $P(X_n=n)=n^{-2}$ and $P(X_n=1)=P(X_n=0)=\frac{1}{2}(1-n^{-2})$. Show $(1/\sqrt{n})(\sum_{m=1}^{n}X_n-n/2)$ converges weakly to a normal distribution as $n \rightarrow \infty$.Thoughts: My professor...- joypav
- Thread
- Convergence Distribution Normal Normal distribution Weak
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB A Subset of a Graph with No Perfect Matching
I think I may have a proof.. I will post it here so the question is complete, but also feel free to make sure it is correct! Proof: Case i: $S = \emptyset$ Then both 1. and 2. are obviously true. Case ii: $S \ne \emptyset$ Assuming 1. to be true, choose the smallest possible $S$ satisfying...- joypav
- Post #2
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB A Subset of a Graph with No Perfect Matching
The problem given is... Let G be a graph with no perfect matching. Then, for some $S \subset G$, 1. $|S|<O(G−S)$ 2. Each vertex in S is adjacent to vertices in at least three odd components of $G−S$. (where $O(G−S)$ is the number of odd components of $G−S$) Number 1. is the contrapositive of...- joypav
- Thread
- Graph
- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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J
MHB Integral Over Unit Sphere of Inner Product
Problem: Prove that for any $x \in R^n$ and any $0<p<\infty$ $\int_{S^{n-1}} \rvert \xi \cdot x \rvert^p d\sigma(\xi) = \rvert x \rvert^p \int_{S^{n-1}} \rvert \xi_1 \rvert^p d\sigma(\xi)$, where $\xi \cdot x = \xi_1 x_1 + ... + \xi_n x_n$ is the inner product in $R^n$. Some thinking... I...- joypav
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- Inner product Integral Product Sphere Unit
- Replies: 1
- Forum: Topology and Analysis
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J
MHB Integration in Polar Coordinates (Fubini/Tonelli)
Thank you! Makes sense. I wonder why we haven't seen the "push forward"? (Wondering) In the very first integral, is that meant to be $d\lambda$?- joypav
- Post #3
- Forum: Topology and Analysis
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J
MHB Integration in Polar Coordinates (Fubini/Tonelli)
Let $S^{n-1} = \left\{ x \in R^2 : \left| x \right| = 1 \right\}$ and for any Borel set $E \in S^{n-1}$ set $E* = \left\{ r \theta : 0 < r < 1, \theta \in E \right\}$. Define the measure $\sigma$ on $S^{n-1}$ by $\sigma(E) = n \left| E* \right|$. With this definition the surface area...- joypav
- Thread
- Coordinates Integration Polar Polar coordinates
- Replies: 4
- Forum: Topology and Analysis
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J
MHB Finding Lebesgue Decomposition for a Measure Defined by an Integral
Ahh okay, then it is as simple as $\nu = \nu_1 + \nu_2$, where $\nu_1=\nu$ and $\nu_2 \equiv 0$?- joypav
- Post #3
- Forum: Topology and Analysis