Recent content by jp6373

The question was given by my professor. i am unsure where he got it from. I have no idea what constant curvature and zero torsion is.

i think i have got it. when we dot the 2 vctors, they give a Zero answer. this means that they are perpendicular to each other. now, they must be the radius of the circle. so the length of the 2 vectors are equal. so we end up with a= +_ root 12.

if i dot the vectors, what will i get? anthing of value?

lol, now what,we learned about the derivitive and then the dot product...i don't see how the der. will work here at all, any ideas on the dot product?

ok, tell me if this makes sense: x= 2 cost + a Sin t y= a Cos t + Sin t z = 3 Cos t - a Sin t then do we have 2 vectors? cost < 2,a,3 > and Sin t < a, 1,-a>...not sure if this can be done. I've never used Cos and Sin as scalar...

yes sir, that is the exact wording. copy and pasted

Homework Statement 2.2) Prove or disprove that there is a value of a for which the image of the following vector function is a circle: r(t) = < 2cos t + a sin t, a cos t + sin t, 3 cos t - a sin t >. any help will be appreciated