Recent content by jreis

Wait doesn't fermat's little theorem say 210 = 1 mod 11 ? That's all I need right

Where are the 10 and 20 coming from?

So do what RUber said? I feel like there is a faster way than checking 10 powers of 2... I know the answer is false from doing that. However, you are hinting at something simpler but I really don't know what. I just started learning modules.

Oh good point... I'm not sure, I'm trying to work this out

Homework Statement Determine whether there is a positive integer k so that the congruence is satisfied. 2k ≡ 1 (mod 11)Homework Equations gcd(2k,11) = 1The Attempt at a Solution Well, I know the answer is false. Because of Fermat's Little Theorem, 2k ≡ 2 (mod 11) But I'm not satisfied with...

Right, I get that. But if I were to add a second vector, how could I show that their sum is also in W?

Yes. I guess that's what I'm confused about

yeah

This is what I'm asking. How do I approach these questions..? I know the 0 vector is in the set, but the other two?

Expressions then.. This is an exact problem out of my textbook, and I'm trying to figure out why W is a subspace holds true.

Hmm, I think for W to be a subspace it needs to: 1) Contain the 0 vector 2) for vectors v and w in W, v+w is also in W 3) for vector v in W, and any real constant c, cv is also in W This would be a 3x3 matrix. I don't see why you're confused? Yes. W = { (3 given equations) : x, y, z are...

I want to know why this subset W is a subspace of R3. W is defined as: | x+2y+3z | | 4x+5y+6z | | 7x+8y+9z | I know the possible subspaces of R3 are the origin itself, lines through the origin, and planes through the origin. Would W be a subspace of R3 simply because there would be...

I wouldn't generalize every person by saying that... Some people learn better through observation. Anyways, thanks.

I think I've figured it out anyway, (again). I hope this IS linear or else I'm still really really off in this process. But I just wasn't understanding the notations, I thought you literally had to multiply <x1, x2> by each column vector, not split it into its components..

It's too late, this is due today. This is the one problem I couldn't answer and it's probably the easiest of them all. I appreciate your help, but it's a shame you guys can't just post the work and answer to the problem so I can learn from it