Recent content by Juke

Yes, got it now. Thanks Vcm = 1.3 * 10/1.8 P = 1.5 * Vcm = 10.83 Ns

0.8+0.5 = 1.3m

I took a guess and tried using the horizontal velocity of 10m/s but that's incorrect as you can see from the answers. So to find the total linear momentum I need the Vcm?

Radius of gyration about axis through centre of mass: 0.29m; moment of inertia about actual rotation axis 2.66 kg m2. (a) Angular velocity 5.56 rad s−1; (b) Angular momentum 14.78 kg m2 s−1; (c) Kinetic energy 41.05 J; (d) Total momentum 10.83 kg m s−1. The centre of mass of the bat is at...

Homework Statement A bat for use in a ball game has total mass M = 1:5 kg and total length ` = 1 m; assume it can be approximated by a thin uniform rod of length `. What is its radius of gyration k_{0} about an axis perpendicular to the bat and through its centre of mass? A player grips...

You've been such great help, I really appreciate. The work-kinetic theorem makes more sense to me after working though this problem. I can't believe I've only just stumbled across this place, it's fantastic. Ill attempt that problem in the morning, it's late where I am. Thanks again.

Ill keep that in mind for when I do problems involving non constant forces. Thanks

Now I got v = 5.08 m/s

Oh I see, 'displacement'!, I worked out the distance. So it should be just 1/2 * cos30.

It should be 1/2 * (2 - cos30), I can see why is isn't what you highlighted. Okay, so now the horizontal work done is [1/2 * (2 - cos30) x 4cos30], and the vertical [1/2 *(1+sin30) x 4sin30] Does it look right?

I know calculus but I don't know what steps you took to set up that integral. I'm aware that the work done is the integral of the F(dot)dr. What is F equal to in that integral?

I've managed to figure out the angle to be 120 degrees. I just learned that the max speed occurs when the force F = 4N acts along the radius. However I'm still stuck trying to find this speed. I've thought about which force does work, isn't it the force due to the fan? If I can remember...

Homework Statement A model land-yacht runs on a horizontal frictionless oval track as shown (viewed from above) in the figure. The curved parts of the track are semi-circles of radius R = 0:5 m; the straight sides have length L = 1 m. The mass of the yacht (including its sails) is m = 0:5...