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J
My initial thought was to approach this using complex contour integration due to the structure of the inverse transform. However, there...
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J
They are mentioned briefly in Arfken, where it is noted that substituting ##t=\ln x## and ##i \omega = s -c## (possibly a typo — perhaps...
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J
Your question could have been phrased more clearly.
Try evaluating your integral by first expressing it as ##\sum_{n=0}^\infty...