Recent content by Julieh

i am still not getting it . but we can continue tommorow , have a blessed night

now how is Q1 equation and Q2 equation look like?

the way i understoond it , its like the ice and water are in equlibrium, meaning they have same or equal temperature and they are now being heated at 60 degree celcius to a steam or what is in your opinion?

The The melted ice turns into water which will be heated and change into steam which is in gas form

Q1+Q2=0 and then Q1 is :[0.250kg*(3030*10^6)+(4.2*10^3)*0.250*60] and i added Q2:[(M*2300000)+(4200*0.300*40)] and when Q1+Q2=O it will be :82500+63000+M2300000+50400=0 M2300000=-195900 M=-195900/2300000 M=-0.85 M=-0.1KG

Homework Statement Suppose that 0.250 kg of ice and 0.300 kg of water in thermal equilibrium are heated to 60°C by being mixed with M kg of steam at 100°C. Use Lice melting = 3.30 x 105 J/kg, Lwater vaporizing= 2.30 x 106 J/kg, and cwater = 4.2 x 103 J/kg°C. (a) Write an expression for Q1, the...