Recent content by JuliusDarius

So, (water weight, 4188)=(Full Pb ball,11340 kg/m^3)-(removed part, 7152 kg/m^3 I think?)

I understand what you mean, I'm just totally lost on how to make up the equation. Thanks for the help everyone so far by the way. Sorry for being so bad at math/physics!

So if I remove 7152 kg/m^3 of lead the balls weight will equal the water's mass. But what about the air in the hole now? And how do I use that to determine how thick the wall needs to be?

So,11340 kg/m^3-X=4,188.79 kg/m^3?

If mass=density*volume then water has a ball of water 2m in diameter is 4,188.79 kg/m^3? And then a ball of lead 2m in diameter would be 11340 kg/m^3? Now I'm not really sure how to use the equation though.

V=4/3∏r1^3 - 4/3∏r2^3. Looks much better. Now what should I do?

Would it just be V=4/3∏r^3-4/3∏r^3?

That I'm not sure if I can do.

Yes I do. I calculated the volume of a sphere with a radius of 1 to be about ~4.18879

Homework Statement Today In class(1st day of physics) the teacher paired us up and told us to figure out how to make a lead ball float in water. The ball has a radius of 1 meter and is made of lead. To make it float we can hollow it out and fill the empty space with air. For this problem we...

I'm not really sure what to write in this situation.

Could you show me how to do that?

1/68.169 2/68.169 3/68.169?

Im not sure how to right an expression for the nth doll.

Would it approach infinity, but never reach it?