Recent content by juronimo

correct, i want to compute the area of the oval type shape in the middle. i took the integral with 0 ≤ r ≤ 2sin(θ) 0≤ θ ≤ ∏/2 ∫∫ (r2cosθ) dr dθ and got 2/3 then i took the integral (5/6)∏ ≤θ ≤ ∏ 0 ≤ r ≤ 2sinθ ∫∫(r2cosθ) dr dθ and got -1/24 i took the...

i see it more of as, computing 0 to pi/2 and having my upperbound be my bottom circle. and then computing 0 to pi/6 and having my upperbound be my top circle. subtracting the second from the first and then doubling it.

I'm adding all 3 integrals up to compute my final area?

im looking at it now. could i use simple geometry to find the intervals of theta? Pythagorean theorem to get the angle on each side with respect to the x axis?

Homework Statement The domain D is the intersection of two disks x^2 +y^2 = 1 and x^2 + (y-1)^2 =1 use polar coordinates to find the double integral ∫∫(x)dA Homework Equations x = rcosθ y = rsinθ r^2 = x^2 + y^2 The Attempt at a Solution I have drawn the circles...