Recent content by JustAverageSkill

Here's another attempt, which yielded the right answer. For m1: m1ax=T-m1gsinθ For m2: m2(-ax)=T-m2g m1ax+m1gsinθ=m2(-ax)+m2g ax(m1+m2)=m2g-m1gsinθ ax=(m2g-m1gsinθ)/(m1+m2)=(5*9.8-10*9.8*.64)/15=-0.92

Could you please write out the correct force equations that I should use to solve for tension and acceleration?

See above please

If one block goes up, the other goes down, I suppose. But how do I quantitate that idea?

I'm not sure what you mean by this. For m1, I have defined positive x to be up and parallel to the ramp. For m2, positive x is directly up.

I tried to write out the equations as follows: m1ax=T - m1gsinθ m2ax=T - m2g Is this correct? Upon solving this I got an answer that is different than the one in the book

Given that fact, how should I proceed?

Hi, I'm JustAverageSkill or JAS for short. Freshman in high school currently taking AP Physics 1:)

Homework Statement The ramp in figure is frictionless. If the blocks are released from rest, which way does the 10 kg block side and what is the magnitude of its acceleration? θ=40°...