Recent content by justbaum30

Thank you very much for your help! It is very much appreciated. Have a good one

Sigh, what a silly mistake. Here we go again: Zth1 = (L)(R1)/(R1+L) = 2.95+2.46j Eth1 = (L)(E)/(R1+L) = 23.05<89.81 Zth2 = (Zth1+C) || R2 = 1.27-0.23j Eth2 = (R2)(Eth1)/(Zth1+R2+C) = 8.90<107.09 Part (a) is Eth2 For part (b) my understanding was to take the conjugate complex so the answer...

Okay, I am hoping I did this correctly. I ended up getting Eth2 to equal 6.33<39.62 for part (a) and got Zth2 to equal 1.48<5.85 or 1.84 + 0.19j. Zth1 = (L)(R1)/(R1+L) = 5+6j Eth1 = (L)(E)/(R1+L) = 23.05<89.81 Zth2 = (Zth1+C) || R2 = 1.84+0.19j Eth2 = (R2)(Eth1)/(Zth1+R2+C) = 6.33<39.62 For...

I am pretty sure it is supposed to be: Zth2 = (Zth1+C) || R2?

In the second circuit though wouldn't two of the three structures (Zth, C, and R2) have to be in series? I don't understand how all three could be in parallel?

Haha, thank you very much. I will try this method and post back, hopefully understood!

So are you saying to take E, R1, and L as a circuit, find the Eth and Zth of that, and then treat Eth, Zth, C, and R2 as a circuit and find the Eth2 and Zth2 of that? Then you would be able to use this second circuit to find the voltage across R2 using the voltage divider rule? Hopefully this...

Hmm, I am somewhat confused then. First to find Zth I must: Zth = (R2+C1) || (L1) || (R1) I got this to equal, in phasor form, 18.42 < -172.38. Then isn't this the answer for (b) or am i misunderstanding the definition of "matched load"? As for (a) can I simply do: Eth =...

Homework Statement (a) For the circuit above find the physical parameters of the Thevenin equivalent source with respect to terminals “a” and “b”. Assume that the resistances and reactances of the circuit are given at signal frequency 1 MHz. (b) Find the impedance of the matched load for that...