The forums are not loading correctly for me, so it will not let me input equations, but the sum of the forces in the x direction are = to F0 - (coefficient of friction * normal force) = mass * acceleration. Then I have to solve that for acceleration.
Okay, but I still have no idea where you get the equation from that. Could you upload a picture of what you did?
Friction divided by normal is equal to the coefficient of friction right? Vertically you have normal - weight = 0 and horizontally you have the pushing force - the friction force...
I don't know what a cross section diagram is. I don't know how you got that equation for number one.
For number 2, there are four forces not three right? Normal, Weight, Force, and Friction.
I don' know how to do that for number one. I also don't understand what your asking for number two. This is extremely frustrating. I don't have a clue where to look for this either.
Thank you and my apologies!
For the first problem, I understand that the ball is moving at a horizontal with uniformed circular motion, which is arad=V2/R. The Fnet=marad=mv2/R. The \sumFy=0 I think and \sumFx=marad? I'm not exactly sure about that or how to use the height depicted as y...
I am having a very hard time understanding these two problems I have attached. I have read the chapter in our text over and over again, but do not see the correlation or how to exactly set the problems up. I recently had surgery on my writing hand and missed a large portion of this class, so I...