Recent content by jzl0027

can i just integrate the whole equation with respect to x so that: y'=x2 - y + C plug in values and C=1 so that y' + y = x2 + 1 I(x) = e(integral of 1 dx) = ex (e^x)y = \int(x2+1)ex dx = (x2 - 2x + 3)ex + C y = -3e-x + x2 - 2x + 3

all we've covered in class is first order

no not really... not in terms of what that would mean for the problem I'm working on

i put it in my ti-89 and came up with y = -3e^-x + x^2 - 2x + 3 it would help for somebody to give an example (preferably the actual problem I'm working on) what gwillim did would've helped out a lot if it'd been right... I'm not asking for the answer ... i just need to know how to work the...

Homework Statement Solve the initial value problem y" = 2x - y' , y'(0) = 1 , y(0) = 0 I know this is probably a simple problem but I don't have a book for the class yet and the teacher didn't really cover this material in class but we still have homework due on monday so i need to figure...