can i just integrate the whole equation with respect to x so that:
y'=x2 - y + C
plug in values and
C=1 so that
y' + y = x2 + 1
I(x) = e(integral of 1 dx) = ex
(e^x)y = \int(x2+1)ex dx = (x2 - 2x + 3)ex + C
y = -3e-x + x2 - 2x + 3
i put it in my ti-89 and came up with y = -3e^-x + x^2 - 2x + 3
it would help for somebody to give an example (preferably the actual problem I'm working on)
what gwillim did would've helped out a lot if it'd been right... I'm not asking for the answer ... i just need to know how to work the...
Homework Statement
Solve the initial value problem y" = 2x - y' , y'(0) = 1 , y(0) = 0
I know this is probably a simple problem but I don't have a book for the class yet and the teacher didn't really cover this material in class but we still have homework due on monday so i need to figure...