@Mark44 I integrated the partially differentiated equation, not the ones you said were M and N. I mixed them up, sorry.
Those integrated are
M = (x2y2)/2 - 2xy + h(y)
N = (x2y2)/2 - 2xy + h(x)
They are the same. LCKurtz's link is a bit complicated and I fail to see how to apply it to this...
I'm sorry, that example confused me further, though I'm sure it is helpful.
The method I have discerned from my notes is that I should partial differentiate the equation, to see if the equation is exact. Upon finding that it is, I need to integrate My(?) and then the rest of my notes aren't...
Thank you for your thorough response!
Is my partial differentiation correct then?
When I integrated I got
M = x2y - 2x + h(y)
N = xy2 - 2y + h(x)
With h(y) and h(x) being those two constants of integration you mentioned.
I'm confused on what you mean by "adjust things so that the two answers...
Homework Statement
Use the "mixed partials" check to see if the following differential equation is exact.
If it is exact find a function F(x,y) whose differential, dF(xy) is the left hand side of the differential equation. That is, level curves F(xy)=C are solutions to the differential...