Recent content by KatieMariie

I was also instructed to use the above formula (OP) by my tutor; however I'm somewhat concerned that the R'p equation looks odd. I have completed the calculations as instructed and found b) = 1210.19 Ohms (2 dp), i had not questioned my answer until i came across this post. Can anyone confirm...

With regards to simplifying: (V1-V20/Z1)-(V20/Z4)+(V20-V3/Z5)+(V2-V20+V3/Z3)=0 to isolate V20; At what point do we substitute the known values? before or after simplification? I've substituted before simplification, and started to simplify, so now have the following...

Sorry, i thought this forum was for guidance? or am i mistaken? I'm not looking the the whole answer obviously, just a bit of guidance would be appreciated. The two nodes connecting Z4, Z2 and Z3 are both essential, along with the lowermost. but they all appear to have four branches. normally...

Now we're working on part b and are stumped. not sure where to begin with our reference node?

No not exactly, I've factored the equation differently. but no worry! in the mean time i'd had a chat with my work colleague who's on the same course and between us we've managed to figure it out. :) thanks!

Hi Guys, I've got the same as above^^; but am not sure on how to proceed with my mesh analysis - how do i solve the system of equations?

Hi, thankyou, that seemed to be the case, I've now finised the question. Thanks for you help. :)

Thankyou, I've realized my mistake, I've had the correct method all along, just one of my values was out by 0.1. Typical. Thanks again.

Sorry, not 'as above', that applies to another thread!

Hi, apologies for the lack of detail in the first post. So i have 103.75-j69.16 for the current source, as stated above, and also have the circuit written out as the current source with Rn on one parallel branch, and the Load on the other. To convert the current to voltage i used...

So i have 103.75-j69.16 for the current source, as stated above, and also have the circuit written out as the current source with Rn on one parallel branch, and the Load on the other. To convert the current to voltage i used (103.73-j69.16)*(j2.4) = 165.98 + j248.95, so this becomes the voltage...

How did you guys get on with part c? I've got so far as a refined circuit with a current source in parallel with Rn (j2.4) and the 35+j35.707 Load, but can't seem to get past this as my numbers don't add up! I'm not getting the same as i did in a or b?

Hi gneill, I've been away on work for a while and have come back to this question. I've tried the above, as in converted the current back into a voltage source ( via ohms law, so now V = 0.601355-j17.82945 ?!) and then used ohms law to calculate the current in the series circuit, but it...

waheey, progress made! there is hope for me yet...

So I've now got a simplified circuit; current source In (103.75-j69.167) in parallel with Rn (j2.4) and the Load (35+j35.70714) Now is it a case of converting this current source back into a voltage and a circuit re-drawn as a voltage source with Rn and L in series? I want to confirm this...