Recent content by Katy

is due at 1pm or 9am? Anyway what I got when string is doubled is aplitude = A/2 Mass per unit length = 2u speed =(T/2u)= 2^-0.5 v angular frequence =2pi/9T/2) = 4pi/T = 4pi f period = T/2 tension =4 P 1/2 (2u) (2pi f)^2 (A/2)^2 (2^-0.5 v) = u 16 (pi f)^2 (1/4) A^2(2^-0.5 v) =...

Hi, I need the help with the same problem, Well I know that Power is equal to P = 1/2 (u)(w)^2(A)^2(v). And when string is doubled the tension stays the same and length is reduced by half and the mass per unit length is increased by two. So the new equation becomes: P = 1/4(u)(w)^2(A)^2(v)...