Recent content by kaylajrox

no, for the most part it does make sense.

that's okay. See i was thinking i could use V^2=V0^2+2ad and plug in 0 for the velocity, plug in the initial velocity that i got in part a, and plug in g for acceleration and solve for d. But since at this point it would not be moving, then the acceleration would also be 0 too. So, I am not sure

i think i figured out the velocity in part a, but i am having a lot of trouble finding the acceleration to find the distance.

Homework Statement A 2kg block is pushed against a spring of force constant k=400 N/m, compressing it .22m. When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless incline with a slope of 37 degrees. a.) what is the speed of the block as it...