Recent content by keeper54

got it. thanks so much for your help. sorry once again for making things so difficult. I'm goin' to bed.

i did it again and still got .48308

don't know where i went wrong...

OK. got that. so... 2(2)/9.8(1.5*1.5)- sin30 / -cos30 = mu. mu=-.48

Understanding everything except for that darn mu thing. I'm really sorry I'm making this so hard.

still not answering the mu thing, though. Sorry...lol. d=1/2 (9.8sin30 - [mu]9.8cos30)

but mu is a value, isn't it (and one that I don't have, at that)? So how do I find accel. without mu? I'm sorry if I'm being difficult, but as you can see, this isn't my strongest subject :).

so how would i find mu?

I plugged everything in so that it was a=9.8sin30=4.9m/s/s. This is wrong, though. The back of the book says it should be 1.78m/s/s. What's wrong?

friction there is definately friction involved, because one of the questions is asking for the coefficient of friction.

hey i was wondering if anybody could show me how to do a problem that contains multiple parts: 55. A 3.00 kg block starts from rest at the top of a 30.0° incline and accelerates uniformly down the incline, moving 2.00 m in 1.50 s. a. Find the magnitude of the acceleration of the...