Recent content by Keesjanss

Oh I think I got it correct now : DSolve[{28 y''[t] + 3 y'[t] + 13 y[t] == 0, y[0] == 1, y'[0] == 1}, y[t], t] and now there no constants anymore in the equation. But now is the next question : What is the natural frequency w0 of this system? Someone who knows that?

Ok, but how do I exactly add those initial conditions in the equation I have now : DSolve[28''y[t]+3y'[t]+13y[t]==0,y[t],t] So where in the equation has the ''y[0]==1 andd y'[0]==1 be placed and which brackets do I have to use?

This is what I have so far DSolve[28 y''[t] + 3 y'[t] + 13 y[t] == 0, y[t], t] {{y[t] -> E^(-3 t/56) C[2] Cos[(Sqrt[1447] t)/56] + E^(-3 t/56) C[1] Sin[(Sqrt[1447] t)/56]}} Now is my question, how do I lose the constants C[2] and C[1]. I think it has something to do with that y[0]=1...

Hello, I am currently working on a problem, but at the moment I am stuck. I just don't know how to solve the problem so I hope someone can help me with it. This is the question 1a : Consider the standard mass-damper-spring system: m y''+γ y'+k y=u where the constants have the following...