Oh I think I got it correct now :
DSolve[{28 y''[t] + 3 y'[t] + 13 y[t] == 0, y[0] == 1, y'[0] == 1},
y[t], t]
and now there no constants anymore in the equation.
But now is the next question : What is the natural frequency w0 of this system?
Someone who knows that?
Ok, but how do I exactly add those initial conditions in the equation
I have now : DSolve[28''y[t]+3y'[t]+13y[t]==0,y[t],t]
So where in the equation has the ''y[0]==1 andd y'[0]==1 be placed and which brackets do I have to use?
This is what I have so far
DSolve[28 y''[t] + 3 y'[t] + 13 y[t] == 0, y[t], t]
{{y[t] ->
E^(-3 t/56) C[2] Cos[(Sqrt[1447] t)/56] +
E^(-3 t/56) C[1] Sin[(Sqrt[1447] t)/56]}}
Now is my question, how do I lose the constants C[2] and C[1]. I think it has something to do with that y[0]=1...
Hello,
I am currently working on a problem, but at the moment I am stuck. I just don't know how to solve the problem so I hope someone can help me with it. This is the question
1a : Consider the standard mass-damper-spring system:
m y''+γ y'+k y=u
where the constants have the following...