Recent content by Keldric

Thanks for the answers.

in my previous post, I already used the value for L. L0=t(100)/(1+100α)? L0=100.24(100)/(1+100α) α=2.4*10^-5 L0=10048.0576 ? Is there a list of α of a certain material at different temperatures? if there is one, please show me. Another thing, please show me your reference material. is it a...

According to this site (http://www.wisegeek.com/what-is-the-highest-possible-temperature.htm), the highest possible temperature is 1.41679 x 1032 Kelvin. If we are going to use T0≥ 41666 2/3, then T≥0 if ΔT=-41666 2/3. The final temperature is now possible to be achieved (T≥0). Can you...

t0=t(100)/(1+100α)? T0=100.24(100)/(1+100α) α=2.4*10^-5 t=10048.0576 ?

There is another question: If L=L0(1+α∆T) then it is possible for L to be zero? 0=L0(1+α∆T) Suppose L0 is not equal to zero. 0=1+α∆T ∆T= -1/α α is a very small number. for example, aluminum again. α = 2.4x10-5. then ∆T=-41666 2/3. It is a very low temperature and I'm not sure if...

1.Homework Statement . Can someone give me more accurate mathematical models on thermal expansion? for example, linear expansion. 2.Relevant equations L=L0(1+α∆T) this equation is not accurate. for example. When an object 100m long at 0oC (example: aluminum, α=2.4x10-5) is heated to...