For 12x - 6y - 5z + 6 = 0, the three intercepts yield -1/2, 1 and 6/5.
So the plane "opn" should be (-2 1 5/6).
Am I doing it right?
There's also a question I want to ask.
If I reduced the point p to (2, 2, 3), I'd get a plane 2x - 1y - 1z + 1 = 0 which is different from 12x - 6y...