Recent content by kevin heck

Sorry for the impatience. I appreciate the help you have given me especially since you are just volunteering. Thank you. :) d) Calculate the net acceleration at the equator. That is exactly how it appears.

so to get the rotation of Earth i would take its radius and divide by 9.80 m/s^2?

hello?

my units for T^2 are off. is this not the period of Earth? so i took 365 days and broke it down into seconds and came up with 3.5136*10^7 seconds. then i squared that number. where did i go wrong?

then it goes on to tell me to calculate the net acceleration at the equator. i believe i would do this by using formula net acceleration= mass* acceleration?

thank you very much :)

i am doing my physics 20 by corrospondance right now.

what i did was substitute in my values for the second equation previous. so i got a= 4 (pi^2) (6.391*10^6m)/ (3.1536*10^7m/s^2)^2 and came up with an answer of 2.537*10^-7 m/s^2. i was wondering if i am going in the right direction? i am a 30 year old man who is going back to school for my...

is that the step in the right direction?

or a= 4(pi)squared r/ Tsquared

I believe it is a= v^2/r.

I'm not really clear on what the omega is all about. I haven't come across this term yet. what i understand is i should use the equation F = m v^2/r, but i thought the mass had nothing to do with the centripetal acceleration. I'm confused.

Homework Statement Earth is commonly thought of as a sphere, but this is not true. Because of Earth's spin, it closely resembles an oblate spheroid, which is just a fancy name for "shaped like a squashed orange". The effect of this spin is a tidal bulge that forms at the equator so that the...