b/c at the top of the trajectory, it's 0 m/s, and I use time as 2.05 instead of 4.1...
But now I think about it, time shouldn't be half... Great, back to square one.
You know what, nvm the thread. I think I am better off figuring it out myself.
using the 2 kinematic equations previously
0 = v1^2 + 2*a*v1*t + a^2 * t^2
this is what I've done on post #5, i knew everything except a in that equation, so I solved for it and it came out to -9.8. Which can't be right b/c of the field, so where did I go wrong?
i've tried d = v1t + .5 at^2
still have 2 variables. So I did a system of equations with the first kinematic equation. Subbing d into a, hoping to find the new a and it came out to -9.8. lol...
...I'm all for not doing other peoples homework for them, but you guys are hiding the info like it's...
Well you really haven't said anything I don't already know. I've said force gravity and electric field will deccelerate the ball... and that's where I am stuck
Well my plan was to use V = E d
So I need to find E and d and I'll have the problem solved.
I used V2^2 = V1^2 + 2ad
v2 is 0, v1 is 20.1, and i used 9.8 for a.
So d came out to 20.6. But I don't think that's correct because I didnt account for the acceleration due to the electric field? So...