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Minimum motor power for a mechanical horizontal sieving machine
thank you lnewqban for your time , i know these informations , i want to know if my calculations, used equations and last result are correct . regards.- khodournajem
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- Forum: Engineering and Comp Sci Homework Help
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Minimum motor power for a mechanical horizontal sieving machine
r = 2.5 l=10 cm angle = 0 (maximum connecting rode elongation) w = 0.5 (30 rpm) n=10/2.5 = 4 so the acceleration is 1.5×0.5×0.5(1 + 1/4 ) = 0.4 m/s friction force = 10*9.81*0.3 = 29.4 Newton. Crank force is the mass of the object into acceleration. So crank force = 10 × 0.4 = 4 Newton...- khodournajem
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- Horizontal Machine Mechanical Minimum Motor Motor power Power
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- Forum: Engineering and Comp Sci Homework Help