Recent content by Kincaid

  1. K

    Heat transfer by conduction in a truncated cone

    I am so thankful for your help on this. I feel like I have a much better understanding of the material now as well. Thanks again K
  2. K

    Heat transfer by conduction in a truncated cone

    I neglected the 0 part of the integration. I now have a value of 2.24 kW which makes more sense.
  3. K

    Heat transfer by conduction in a truncated cone

    I think I must have made a mistake somewhere because I end up with a negative heat transfer which doesn't make sense. My integration of dx/A(x) yields (1/PI)*(h/(r2-r1))*(r1+(r2-r1)*x/h)^-1*(-1) between 0 and h. This yields (1/PI)*(h/(r2-r1))*(1/r2)*(-1). Multiplying this to the opposite...
  4. K

    Heat transfer by conduction in a truncated cone

    Thanks so much. This makes it really clear. Because the area is constantly changing as we move through the cone we must transform the area into terms of one of the available variables, in this case the height. Once this is done we can take the integral with respect to that variable in...
  5. K

    Heat transfer by conduction in a truncated cone

    So then can it be said that q1=k1A1T1 and q2=k2A2T2 and the overall heat transfer is equal to q1/x? Or are you saying that q=0? Or do I need to use constant specific heats to solve this question to get the change in enthalpy and use that to get q? I'm afraid this has just...
  6. K

    Heat transfer by conduction in a truncated cone

    1. The problem statement A truncated cone 30cm high is made of Aluminum. The dia at the top is 7.5cm, and 12.5cm at the bottom. The lower surface is maintained at 93 deg C, the upper surface at 540 deg C. the other surface is insulated. Assuming 1 dimensional heat flow, calculate the rate of...
  7. K

    Finding the Volume of a tetrahedron using Spherical Coordinates

    Find the volume of a tetrahedron under a plane with equation 3x + 2y + z = 6 and in the first octant. Use spherical coordinates only. The answer is six. x=psin(phi)cos(theta) y=psin(phi)sin(theta) z=pcos(phi) I've been trying to figure out the boundaries of this particular...
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